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For even in the very best case any block of cells in the input can never be compressed to less than one cell in the output.
The instruction being executed is indicated at each step by the position of the dot on the left, while the numbers in each of the two registers are indicated by the gray blocks on the right.
Redundancy can in principle be estimated by breaking text into blocks of length b , then looking for the limit of the entropy as b  ∞ (see page 1084 ).
And they can be extended somewhat by using visual block diagrams or flowcharts.
Implementation [of tag systems] With the rules for case (a) on page 94 given for example by {2, {{0, 0}  {1, 1}, {1, 0}  {}, {0, 1}  {1, 0}, {1, 1}  {0, 0, 0}}} the evolution of a tag system can be obtained from TSEvolveList[{n_, rule_}, init_, t_] := NestList[If[Length[#] < n, {}, Join[Drop[#, n], Take[#, n] /. rule]]&, init, t] An alternative implementation is based on applying to the list at each step rules such as {{0, 0, s___}  {s, 1, 1}, {1, 0, s___}  {s}, {0, 1, s___}  {s, 1, 0}, {1, 1, s___}  {s, 0, 0, 0}} There are a total of ((k r + 1 - 1)/(k - 1)) k n possible rules if blocks up to length r can be added at each step and k colors are allowed.
And this makes it reasonable to expect that with appropriate genetic programs the chemical building blocks of life on Earth should in principle allow a vast range of forms.
Implementation [of operators from axioms] Given an axiom system in the form {f[a, f[a, a]]  a, f[a, b]  f[b, a]} one can find rule numbers for the operators f[x, y] with k values for each variable that are consistent with the axiom system by using Module[{c, v}, c = Apply[Function, {v = Union[Level[axioms, {-1}]], Apply[And, axioms]}]; Select[Range[0, k k 2 - 1], With[{u = IntegerDigits[#, k, k 2 ]}, Block[{f}, f[x_, y_] := u 〚 -1 - k x - y 〛 ; Array[c, Table[k, {Length[v]}], 0, And]]] &]] For k = 4 this involves checking nearly 16 4 or 4 billion cases, though many of these can often be avoided, for example by using analogs of the so-called Davis–Putnam rules.
Repeats of a digit block b give numbers that solve Fold[(#1 2 - #2) &, x, b]  x .
For sequences of black and white squares, for example, models that work as above by just assigning probabilities to fixed blocks of squares are by far the most common.
Using these remainders—which are shown inside each square—the color of a particular square can be determined by a simple lookup in the repeating block shown on the bottom left.
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